The currents, \[I,{{I}_{Z}}\] and \[{{I}_{L}}\] are respectively.
[JEE Main Online Paper ( Held On 11 Apirl 2014 )
A) 15 mA, 5 mA, 10 mA
B) 15 mA, 7.5 mA, 7.5 mA
C) 12.5 mA, 5 mA, 7.5 mA
D) 12.5 mA, 7.5 mA, 5 mA
Correct Answer: D
Solution :
Here, \[R=4k\Omega =4\times {{10}^{3}}\Omega \] \[{{V}_{i}}=60V\]Zener voltage \[{{V}_{z}}=10V\] \[{{R}_{L}}=2k\Omega =2\times {{10}^{3}}\Omega \] Load current, \[{{I}_{L}}=\frac{{{V}_{z}}}{{{R}_{L}}}=\frac{10}{2\times {{10}^{3}}}=5mA\] Current through \[R,I=\frac{{{V}_{i}}-{{V}_{z}}}{R}\] \[=\frac{60-10}{4\times {{10}^{3}}}=\frac{50}{4\times {{10}^{3}}}=12.5mA\] Fom circuit diagram, \[I={{I}_{z}}+{{I}_{L}}\] \[\Rightarrow \]\[12.5={{I}_{z}}+5\]\[\Rightarrow \]\[{{I}_{z}}=12.5-5=7.5mA\]
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