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JEE Main & Advanced JEE Main Paper (Held On 11 April 2014)

  • question_answer
    In the circuit diagrams (A, B, C and D) shown below, R is a high resistance and S is a resistance of the order of galvanometer resistance G. The correct circuit, corresponding to the half deflection method for finding the resistance and figure of merit of the galvanometer, is the circuit labelled as:   [JEE Main Online Paper ( Held On 11 Apirl  2014 )

    A) Circuit A with G\[\frac{RS}{(R-S)}\]

    B) Circuit B with G = S

    C) Circuit C with G = S

    D) Circuit D with G = \[\frac{RS}{(R-S)}\]

    Correct Answer: D

    Solution :

    The correct circuit diagram is D with galvanometer resistance\[G=\frac{RS}{R-S}\]


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