A) \[F{{e}^{2+}}<Al<B{{r}^{-}}\]
B) \[B{{r}^{-}}<F{{e}^{2+}}<Al\]
C) \[Al<B{{r}^{-}}<F{{e}^{2+}}\]
D) \[Al<F{{e}^{2+}}<B{{r}^{-}}\]
Correct Answer: D
Solution :
Reducing character decreases down the series. Hence the correct order is \[Al<F{{e}^{2+}}<B{{r}^{-}}\]You need to login to perform this action.
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