A) \[{{(C{{H}_{3}})}_{3}}N\]
B) \[{{(Si{{H}_{3}})}_{3}}N\]
C) \[P{{(C{{H}_{3}})}_{3}}\]
D) \[P{{(Si{{H}_{3}})}_{3}}\]
Correct Answer: B
Solution :
In case of \[N{{\left( Si{{H}_{3}} \right)}_{3}}N\]atom is \[s{{p}^{2}}\] hybridised, the lone pair is present in 2p orbital and it is transferred to empty d orbital of Si forming \[d\pi -p\pi \] bond. Hence nitrogen with \[s{{p}^{2}}\]hybridization has trigonal planar shape.
You need to login to perform this action.
You will be redirected in
3 sec
