A) \[\frac{2h}{\mu }+\frac{v_{o}^{2}}{2\mu g}\]
B) \[\frac{h}{\mu }+\frac{v_{o}^{2}}{2\mu g}\]
C) \[\frac{h}{2\mu }+\frac{v_{o}^{2}}{\mu g}\]
D) \[\frac{h}{2\mu }+\frac{v_{o}^{2}}{2\mu g}\]
Correct Answer: B
Solution :
Initial speed at point A, \[u={{v}_{0}}\] Speed at point B, v = ? \[{{v}^{2}}-{{u}^{2}}=2gh\] \[{{v}^{2}}=v_{0}^{2}+2gh\] Let ball travels distance ?S? before coming to rest\[S=\frac{{{v}^{2}}}{2\mu g}=\frac{v_{0}^{2}+2gh}{2\mu g}\] \[=\frac{v_{0}^{2}}{2\mu g}=\frac{2gh}{2\mu g}=\frac{h}{\mu }+\frac{v_{0}^{2}}{2\mu g}\]You need to login to perform this action.
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