JEE Main & Advanced JEE Main Paper (Held On 11 April 2015)

  • question_answer
    An experiment takes 10 minutes to raise the temperature of water in a container from \[0{}^\circ C\] to \[100{}^\circ C\] and another 55 minutes to convert it totally into steam by a heater supplying heat at a uniform rate. Neglecting the specific heat of the container and taking specific heat of water to be \[1\text{ }cal/g\text{ }{}^\circ C\], the heat of vapourization according to this experiment will come out to be: [JEE Main Online Paper (Held On 11 April 2015)]  

    A)  530 cal/g

    B)  540 cal/g

    C)  550 cal/g

    D)  560 cal/g

    Correct Answer: C

    Solution :

     550 cal/g


You need to login to perform this action.
You will be redirected in 3 sec spinner