A) 400
B) 406
C) -400
D) -496
Correct Answer: C
Solution :
The general term is second bracket is \[^{8}{{C}_{r}}{{\left( 2{{x}^{2}} \right)}^{8-r}}{{\left( -\frac{1}{x} \right)}^{r}}\] Total exponent of x is \[16-3r\] Term independent of \[x=1x\]exp. of\[{{x}^{0}}+(-1)+\exp .\]of\[x+3\times \exp .\]of\[.\frac{1}{{{x}^{5}}}\] \[=0{{-}^{8}}{{C}^{5}}{{2}^{3}}\left( -1 \right)+3\left( ^{8}{{C}_{7}}2(-1) \right)\]\[=-400\]You need to login to perform this action.
You will be redirected in
3 sec