A) \[(1,{{2}^{0.6}})\]
B) \[({{2}^{-0.4}}1,{{2}^{0.6}})\]
C) \[({{2}^{-0.6}},1)\]
D) \[({{2}^{-0.4}},1)\]
Correct Answer: D
Solution :
\[f(x)=\frac{{{\left( 1+x \right)}^{{}^{3}/{}_{5}}}}{1+{{x}^{{}^{3}/{}_{5}}}}\] \[f'(x)=0\Rightarrow x=1\] \[\therefore \] \[f(0)=1,\,\,f(1)=\frac{{{2}^{0.6}}}{2}\] \[={{2}^{-0.4}}\] \[\therefore \]\[f(x)\in \left( {{2}^{-0.4}},1 \right)\]You need to login to perform this action.
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