A) series with C and has a magnitude\[\frac{1-{{\omega }^{2}}LC}{{{\omega }^{2}}L}.\]
B) series with C and has a magnitude\[\frac{C}{({{\omega }^{2}}LC-1)}.\]
C) parallel with C and has a magnitude\[\frac{C}{({{\omega }^{2}}LC-1)}.\]
D) parallel with C and has a magnitude\[\frac{1-{{\omega }^{2}}LC}{{{\omega }^{2}}L}.\]
Correct Answer: D
Solution :
As current leads voltage thusYou need to login to perform this action.
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