A) 25
B) 410
C) 925
D) 1850
Correct Answer: C
Solution :
For metals, there is no free motion but rather oscillation about mean position. Thus these have K.E. & P.E., which are almost equal. i.e. \[P.{{E}_{avg}}=K.{{E}_{avg}}=\frac{3}{2}RT\] \[\therefore \] \[T.E.=K.E.+P.E.\] \[\therefore \] \[T.E.=3RT\]per mole \[\therefore \] specific heat\[C=\frac{3R}{M}\] \[C=\frac{3\times 8.314}{27\times {{10}^{-3}}}\] \[\]You need to login to perform this action.
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