A) \[\frac{m{{\upsilon }^{2}}}{L-nr}\]
B) \[\frac{m{{\upsilon }^{2}}}{L-2nr}\]
C) \[\frac{m{{\upsilon }^{2}}}{2(L-nr)}\]
D) zero
Correct Answer: B
Solution :
As collisions are elastic and masses are equal, velocities of colliding particles get exchanged. \[\Delta \vec{P}\]in each collision with the supports \[=2mv\] Time interval between consecutive collisions with one support \[=\frac{\left( L-2nr \right)\times 2}{v}\] \[{{F}_{avg}}=\frac{\Delta P}{T}=\frac{2mv}{\left( L-2nr \right)2/v}=\frac{m{{v}^{2}}}{L-2nr}\]You need to login to perform this action.
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