A) 9.7
B) 4.9
C) 19.4
D) 14.6
Correct Answer: A
Solution :
At 30cm from the magnet on its equitorial plane \[{{\vec{B}}_{magnet}}=-\overrightarrow{{{B}_{M}}}\](newtral point) so by equating their magnitude \[\frac{{{\mu }_{0}}}{4\pi }\frac{M}{{{r}^{3}}}=3.6\times {{10}^{-5}}\]Tesla \[\frac{{{10}^{-7}}\times M}{{{(0.3)}^{3}}}=3.6\times {{10}^{-5}}\]Tesal \[M=3.6\times 0.027\times {{10}^{2}}=9.7A{{m}^{2}}\]You need to login to perform this action.
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