A) \[y+\sqrt{3}x+2-3\sqrt{3}=0\]
B) \[y-\sqrt{3}x+2+3\sqrt{3}=0\]
C) \[\sqrt{3}y-x+3+2\sqrt{3}=0\]
D) \[\sqrt{3}y+x-3+2\sqrt{3}=0\]
Correct Answer: B
Solution :
\[\tan {{60}^{o}}=\left| \frac{m-\left( -\sqrt{3} \right)}{1+m\left( -\sqrt{3} \right)} \right|\] \[\Rightarrow \] \[{{\left( m+\sqrt{3} \right)}^{2}}={{\left( 1-m\sqrt{3} \right)}^{2}}\] \[\Rightarrow \] \[m=0\]or \[m=\sqrt{3}\] \[\therefore \] equation of required line is \[y+2=\sqrt{3}(x-3)\]i.e., \[y-\sqrt{3}x+2+3\sqrt{3}=0\]
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