A) \[\frac{1}{16}\]
B) \[\frac{9}{16}\]
C) \[\frac{3}{4}\]
D) \[\frac{15}{16}\]
Correct Answer: D
Solution :
\[np=2\] \[npq=1\] \[\Rightarrow \]\[q=\frac{1}{2},p=\frac{1}{2},n=4\] \[p(x\ge 1)=1-p(x<1)\] \[=1-p(x=0)\] \[=1{{-}^{4}}{{C}_{0}}{{\left( \frac{1}{2} \right)}^{0}}{{\left( \frac{1}{2} \right)}^{4}}\] \[=1-\frac{1}{16}\] \[=\frac{15}{16}\]
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