A) \[C{{H}_{3}}CON{{(C{{H}_{3}})}_{2}}\]
B) \[C{{H}_{3}}COC{{H}_{2}}NHC{{H}_{3}}\]
C) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CON{{H}_{2}}\]
D) \[C{{H}_{3}}C{{H}_{2}}COC{{H}_{2}}N{{H}_{2}}\]
Correct Answer: C
Solution :
As carbylamine test is given by primary amines only thus \[{{C}_{3}}{{H}_{9}}N\]should be a primary amine. \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}N{{H}_{2}}\]or\[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ N{{H}_{2}} \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}}\] Amide gives primary amine on reaction with \[B{{r}_{2}}/NaOH.\] Thus, X is \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CON{{H}_{2}}.\]
You need to login to perform this action.
You will be redirected in
3 sec
