A)
B)
C)
D)
Correct Answer: B
Solution :
Initially, when the switch\[{{S}_{1}}\]is closed the current increases \[i={{i}_{0}}(1-{{e}^{-t/\tau }})\]and when the switch \[{{S}_{2}}\]is closed the current starts decreasing exponentially i.e., according to \[{{i}_{0}}{{e}^{-t/\tau }}\]. So, the behaviour of the current can be depicted from the following graph: *As per official answer key. Value \[{{t}_{0}}\]is not specified hence a, b and c may be correct option.You need to login to perform this action.
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