A) lesser nuclear charge and greater first ionisation enthalpy
B) lesser nuclear charge and lesser first ionisation enthalpy
C) greater nuclear charge and greater first ionisation enthalpy
D) greater nuclear charge and lesser first ionisation enthalpy
Correct Answer: A
Solution :
In case of 'Be' electron remove from '2s' orbital while in case of 'B' electron remove from '2p' orbital. '2s' orbital have greater penetration effect then '2p' orbitals. So 'Be' having more I.E. then 'B'You need to login to perform this action.
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