A) \[\left( \frac{1}{3},1 \right)\]
B) \[\left( \frac{1}{3},2 \right)\]
C) \[\left( 1,\frac{7}{3} \right)\]
D) \[\left( \frac{1}{3},\frac{5}{3} \right)\]
Correct Answer: B
Solution :
Let \[B(\alpha ,\beta )\]and \[C(\gamma ,\delta )\] \[\frac{\alpha +1}{2}=-1\Rightarrow \alpha =-3\] \[\frac{\beta +2}{2}=1\Rightarrow \beta =0\]\[\Rightarrow B\left( -3,0 \right)\] Now\[\frac{\gamma +1}{2}=2\Rightarrow \gamma =3\] \[\frac{\delta +2}{2}=3\Rightarrow \delta =4\]\[\Rightarrow C(3,4)\] \[\Rightarrow \]centroid of triangle is\[G\left( \frac{1}{3},2 \right)\]You need to login to perform this action.
You will be redirected in
3 sec