A) \[\left( -\frac{5}{2},-1 \right)\]
B) \[\left( -\frac{5}{2},1 \right)\]
C) \[\left( \frac{5}{2},-1 \right)\]
D) \[\left( \frac{5}{2},1 \right)\]
Correct Answer: C
Solution :
Put \[x2=X\And y+1=Y\] \[\therefore \]given curve becomes \[Y={{X}^{2}}\]and \[Y=X\] tangent at origin is X-axis and tangent at \[A\left( 1,1 \right)\] is \[Y+1=2X\] \[\therefore \]there intersection is\[\left( \frac{1}{2},0 \right)\] \[\therefore \]\[x-2=\frac{1}{2}\And y+1=0\]therefore\[x=\frac{5}{2},y=-1\]You need to login to perform this action.
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