A) \[\sqrt{3}\]
B) \[\frac{1}{\sqrt{3}}\]
C) \[\frac{1}{3}\]
D) \[3\]
Correct Answer: A
Solution :
perpendicular vector to the plane \[\vec{n}\left| \begin{matrix} i & j & k \\ 1 & 2 & -1 \\ -1 & 1 & -2 \\ \end{matrix} \right|=-3\hat{i}+3\hat{j}+3\hat{k}\] Eq. of plane \[-3\left( x1 \right)+3\left( y1 \right)+3z=0\] \[\Rightarrow xyz=0\] \[{{d}_{(2,1,4)}}=\frac{\left| 2-1-4 \right|}{\sqrt{{{1}^{2}}+{{1}^{2}}+{{1}^{2}}}}=\sqrt{3}\]You need to login to perform this action.
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