A) 24
B) 36
C) 12
D) 18
Correct Answer: D
Solution :
\[\underset{x\to 2}{\mathop{\lim }}\,g(x)=\underset{x\to 2}{\mathop{\lim }}\,\frac{\int\limits_{6}^{f(x)}{4{{t}^{3}}dt}}{x-2}\]\[=\underset{x\to 2}{\mathop{\lim }}\,\frac{4.{{f}^{3}}(x).f'(x)}{1}\] \[=4{{f}^{3}}(2)f'(2)=18\]You need to login to perform this action.
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