A) n-Butane and Iso-butane
B) \[{{C}_{2}}{{H}_{4}}\]and \[{{C}_{4}}{{H}_{8}}\]
C) \[{{N}_{2}}{{O}_{4}}\]and\[N{{O}_{2}}\]
D) \[{{C}_{2}}{{H}_{2}}\]and \[{{C}_{6}}{{H}_{6}}\]
Correct Answer: B
Solution :
\[\log \frac{-d[A]}{dt}=\log \frac{d[B]}{dt}+0.3010\] \[\frac{-d[A]}{dt}=2\times \frac{d[B]}{dt}\] \[\frac{1}{2}\times \frac{-d[A]}{dt}=\frac{d[B]}{dt}\]\[2A\xrightarrow[{}]{{}}B\] \[2{{C}_{2}}{{H}_{4}}\xrightarrow[{}]{{}}C{{ & }_{4}}{{H}_{8}}\]You need to login to perform this action.
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