A) \[{{M}_{A}}=50\times {{10}^{-3}}\]and \[{{M}_{B}}=25\times {{10}^{-3}}\]
B) \[{{M}_{A}}=25\times {{10}^{-3}}\] and \[{{M}_{B}}=50\times {{10}^{-3}}\]
C) \[{{M}_{A}}=5\times {{10}^{-3}}\] and \[{{M}_{B}}=10\times {{10}^{-3}}\]
D) \[{{M}_{A}}=10\times {{10}^{-3}}\]and \[{{M}_{B}}=5\times {{10}^{-3}}\]
Correct Answer: C
Solution :
\[5[{{M}_{A}}+2{{M}_{B}}]=125\] \[{{M}_{A}}+2{{M}_{B}}=25\] ....(1) \[2{{M}_{A}}+2{{M}_{B}}=30\] ....(2) from eq. & \[{{M}_{A}}=5\] \[{{M}_{B}}=10\]You need to login to perform this action.
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