A) \[{{(Si{{H}_{3}})}_{3}}N\]is pyramidal and more basic than \[{{(C{{H}_{3}})}_{3}}N\]
B) \[{{(Si{{H}_{3}})}_{3}}N\] is planar and more basic than\[{{(C{{H}_{3}})}_{3}}N\]
C) \[{{(Si{{H}_{3}})}_{3}}N\]is pyramidal and less basic than\[{{(C{{H}_{3}})}_{3}}N\]
D) \[{{(Si{{H}_{3}})}_{3}}N\] is planar and less basic than\[{{(C{{H}_{3}})}_{3}}N\]
Correct Answer: D
Solution :
nitrogen is \[s{{p}^{3}}\]hybrid and pyramidal no back-bonding i.e. more basic Nitrogen \[s{{p}^{2}}\]hybrid and planar due to back bonding and less basic because lone pair is not available for donation.You need to login to perform this action.
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