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JEE Main & Advanced JEE Main Paper (Held on 12-4-2019 Morning)

  • question_answer
    The coefficient of \[{{x}^{18}}\]in the product \[(1+x){{(1-x)}^{10}}{{(1+x+{{x}^{2}})}^{9}}\]is : [JEE Main Held on 12-4-2019 Morning]

    A) -84                  

    B) 84

    C) 126                 

    D) -126

    Correct Answer: B

    Solution :

    \[(1+x){{(1-x)}^{10}}{{(1+x+{{x}^{2}})}^{9}}\]           \[(1-{{x}^{2}}){{(1-{{x}^{3}})}^{9}}\]\[^{9}{{C}_{6}}=84\]


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