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JEE Main & Advanced JEE Main Paper (Held On 12 April 2014)

  • question_answer
    Which of the following arrangements represents the increasing order (smallest to largest) of ionic radii of the given species  \[{{O}^{2-}},{{S}^{2-}},{{N}^{3-}},{{p}^{3-?}}\]   [JEE Main Online Paper ( Held On 12 Apirl  2014 )

    A) \[{{O}^{2-}}<{{N}^{3-}}<{{S}^{2-}}<{{p}^{3-}}\]

    B) \[{{O}^{2-}}<{{p}^{3-}}<{{N}^{3-}}<{{S}^{2-}}\]

    C) \[{{N}^{3}}<{{O}^{2-}}<{{p}^{3-}}<{{S}^{2-}}\]

    D) \[{{N}^{3-}}<{{S}^{2-}}<{{O}^{2-}}<{{p}^{3-}}\]

    Correct Answer: A

    Solution :

                    For isoelectronic species ionic radii decreases as the charge on ion decreases. Further on moving down in a group ionic radii increases. Hence the correct order is\[{{O}^{2-}}<{{N}^{3-}}<{{S}^{2-}}<{{P}^{3-}}\]


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