JEE Main & Advanced JEE Main Paper (Held On 12 April 2014)

  • question_answer
    Interference pattern is observed at 'P' due to superimposition of two rays coming out from a source 'S' as shown in the figure. The value of 'l' for which maxima is obtained at 'P' is: (R is perfect reflecting surface)   [JEE Main Online Paper ( Held On 12 Apirl  2014 )

    A) \[1=\frac{1n\lambda }{\sqrt{3}-1}\]                        

    B) \[1=\frac{(2n-1)\lambda }{2\left( \sqrt{3}-1 \right)}\]

    C) \[1=\frac{(2n-1)\lambda \sqrt{3}}{4\left( 2-\sqrt{3} \right)}\]     

    D) \[1=\frac{(2n-1)\lambda }{\sqrt{3}-1}\]

    Correct Answer:


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