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JEE Main & Advanced JEE Main Paper (Held On 12 April 2014)

  • question_answer
    In the experiment of calibration of voltmeter, a standard cell of e.m.f. 1.1 volt is balanced against 440 cm of potential wire. The potential difference across the ends of resistance is found to balance against 220 cm of the wire. The corresponding reading of voltmeter is 0.5 volt. The error in the reading of volmeter will be:   [JEE Main Online Paper ( Held On 12 Apirl  2014 )

    A) 0. 15 volt                             

    B) 0.15 volt

    C) 0.5 volt                

    D) ? 0.05 volt

    Correct Answer: D

    Solution :

    In a voltmeter \[V\propto l\] \[V=kl\] Now, it is given E = 1.1 volt for \[{{l}_{1}}=440cm\] and V = 0.5 volt for \[{{l}_{2}}=220cm\] Let the error in reading of voltmeter be \[\Delta V\] then, = 400 K and \[(0.5\Delta V)=220K.\] \[\Rightarrow \]\[\frac{1.1}{440}=\frac{0.5-\Delta V}{220}\] \[\therefore \]\[\Delta V=-0.05\]volt


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