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JEE Main & Advanced JEE Main Paper (Held On 12 April 2014)

  • question_answer
    The de-Broglie wavelength of a particle of mass 6.63 g moving with a velocity of 100 \[m{{s}^{-1}}\] is:   [JEE Main Online Paper ( Held On 12 Apirl  2014 )

    A) \[{{10}^{-33}}m\]            

    B) \[{{10}^{-35}}m\]

    C) \[{{10}^{-31}}m\]                            

    D) \[{{10}^{-25}}m\]

    Correct Answer: A

    Solution :

    De Broglie wavelength \[(\lambda )=\frac{h}{mv}\] \[\frac{6.63\times {{10}^{-34}}}{6.63\times {{10}^{-3}}\times 100}={{10}^{-33}}\]                


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