A) \[\frac{{{N}_{A}}}{20}\]
B) \[\frac{{{N}_{A}}}{10}\]
C) \[\frac{{{N}_{A}}}{5}\]
D) \[\frac{{{N}_{A}}}{2}\]
Correct Answer: C
Solution :
\[Cu\xrightarrow[{}]{{}}C{{u}^{++}}+2{{e}^{-}}\]i.e, to deposit 1 mole of Cu at cathode from \[C{{u}^{2+}}SO_{4}^{2-}\]solution = 2 moles of electrons are required i.e, To deposit\[6.35g=\frac{6.35}{63.5}\times 2=\frac{2}{10}=\frac{1}{5}\]moles Thus total no. of electrons required \[=\frac{{{N}_{A}}}{5}\]
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