A) circle
B) hyperbola
C) straight line
D) parabola
Correct Answer: C
Solution :
\[x+2ay+a=0\] ...(1) \[x+3by+b=0\] ...(2) \[x+4ay+a=0\] ...(3) Subtracting equation (3) from (1) \[-2ay=0\] \[ay=0\Rightarrow y=0\] Putting value of y in equation (1), we get \[x+0+a=0\] \[x=-a\] Putting value of x and y in equation (2), we get a + b = 0 a = b Thus, (a, b) lies on a straight lineYou need to login to perform this action.
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