A) \[Xe{{O}_{2}}{{F}_{2}}\]
B) \[XeO{{F}_{4}}\]
C) \[Xe{{O}_{3}}\]
D) \[Xe{{O}_{4}}\]
Correct Answer: D
Solution :
\[Xe{{F}_{6}}+2{{H}_{2}}O\xrightarrow[{}]{Partial}XeO{{F}_{4}}+2HF\] \[Xe{{F}_{6}}+2{{H}_{2}}O\xrightarrow[{}]{Partial}Xe{{O}_{2}}{{F}_{2}}+4HF\]
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