A) \[8.041\times {{10}^{-40}}J\]
B) \[2.680\times {{10}^{-19}}J\]
C) \[1.640\times {{10}^{-18}}J\]
D) \[6.111\times {{10}^{-17}}J\]
Correct Answer: C
Solution :
E = hv \[=6.63\times {{10}^{-34}}\times 2.47\times {{10}^{15}}\] \[=1.640\times {{10}^{-18}}J\]
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