A) 0.71
B) 0.70
C) 0.51
D) 0.20
Correct Answer: A
Solution :
Given \[\frac{(x-10)(x-50)}{(x-30)}\ge 0\] Let\[x\ge 10,x\ge 50\] equation will be true \[\forall x\ge 50\] as\[\left( \frac{x-50}{x-30} \right)\ge 0,\forall x\in [10,30)\] \[\frac{(x-10)(x-50)}{x-30}\ge 0,\forall x\in [10,30)\] Total value of x between 10 to 30 is 20. Total values of x between 50 to 100 including 50 and 100 is 51. Total values of x = 51 + 20 = 71 \[P(A)=\frac{71}{100}=0.71\]You need to login to perform this action.
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