A) \[\frac{1}{6}\]
B) \[\frac{5}{6}\]
C) \[\frac{1}{3}\]
D) \[\frac{2}{3}\]
Correct Answer: A
Solution :
Let C and S represents the set of students who opted for NCC and NSS respectively. \[\therefore \]\[n(C)=40,n(S)=30,n(C\cup S)=20\] Now,\[n(C\cup S)=40+30-20=50\] So, number of students who has opted neither for NCC nor for NSS are \[60-50=10\] So, P(Neither C nor S)\[\frac{10}{60}=\frac{1}{6}\]You need to login to perform this action.
You will be redirected in
3 sec