A) 8
B) 4
C) 6
D) 9
Correct Answer: B
Solution :
Let\[{{S}_{1}}\equiv {{x}^{2}}+{{y}^{2}}-2x-2y-2=0\] \[{{S}_{2}}\equiv {{x}^{2}}+{{y}^{2}}-6x-6y+14=0\] \[\therefore \]\[{{C}_{1}}\equiv (1,1)\]and\[{{C}_{2}}\equiv (3,3).\]You need to login to perform this action.
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