A) 4ml
B) 20ml
C) 2ml
D) 40ml
Correct Answer: D
Solution :
Normality of oxalic acid solution \[=\frac{6.3\times 1000}{63\times 250}=0.4N\]Now from \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[0.4\times 10=0.1\times {{V}_{2}}\] \[{{V}_{2}}=40mL\]You need to login to perform this action.
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