A) 8.1,0.67
B) 8.1,1.2
C) 6.4,1.2
D) 6.4,0.67
Correct Answer: C
Solution :
\[\frac{1}{\lambda }=R\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)\]where R = Rydberg constant\[\frac{1}{{{\lambda }_{32}}}=\left( \frac{1}{4}-\frac{1}{9} \right)=\frac{5}{36}\]\[\Rightarrow \]\[{{\lambda }_{32}}=\frac{36}{5}\] Similarly solving for \[{{\lambda }_{31}}\]and \[{{\lambda }_{21}}\] \[{{\lambda }_{31}}=\frac{9}{8}\]and \[{{\lambda }_{21}}=\frac{4}{3}\] \[\therefore \]\[\frac{{{\lambda }_{32}}}{{{\lambda }_{31}}}=6.4\]and\[\frac{{{\lambda }_{21}}}{{{\lambda }_{31}}}\simeq 1.2\]You need to login to perform this action.
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