A) 2
B) 8
C) 1
D) 4
Correct Answer: B
Solution :
Given parabola is \[{{x}^{2}}=8y\] \[\Rightarrow 4a=8\Rightarrow a=2\] To find: Area of MBC \[A=(-2a,a)=(-4,2)\] \[B=(2a,a)=(4,2)\] \[C=(0,0)\] \[\therefore \]Area\[=\frac{1}{2}\left| \begin{matrix} -4 & 2 & 1 \\ 4 & 2 & 1 \\ 0 & 0 & 1 \\ \end{matrix} \right|\]\[=\frac{1}{2}[-4(2)-2(4)+1(0)]\] \[=\frac{-16}{2}=-8\approx 8\]sq. unit (\[\because \] area cannot be negative)You need to login to perform this action.
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