A) 2,5,16
B) 8,2,5
C) 5,2,16
D) 5,8,4
Correct Answer: A
Solution :
\[XMnO_{4}^{-}+Y\,{{C}_{2}}O_{4}^{--}+Z{{H}^{+}}\] \[X\,M{{n}^{++}}+2YC{{O}_{2}}+\frac{Z}{2}{{H}_{2}}O\]First half reaction \[MnO_{4}^{-}\xrightarrow[{}]{{}}M{{n}^{++}}\] .... (i) On balancing \[MnO_{4}^{-}+8{{H}^{+}}+5{{e}^{-}}\xrightarrow[{}]{{}}M{{n}^{++}}+4{{H}_{2}}O\]....(ii) Second half reaction \[{{C}_{2}}O_{4}^{-}\xrightarrow[{}]{{}}2C{{O}_{2}}\] (iii) On balancing \[{{C}_{2}}O_{4}^{-}\xrightarrow[{}]{{}}2C{{O}_{2}}+2{{e}^{-}}\] ....(iv) On multiplying eqn. (ii) by 5 and (iv) by 2 and then adding we get \[2MnO_{4}^{-}+5{{C}_{2}}O_{4}^{--}+16{{H}^{+}}\xrightarrow[{}]{{}}\] \[2Mn_{{}}^{--}+10C{{O}_{2}}+8{{H}_{2}}O\]
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