A) \[-\frac{GMm}{2R}\]
B) \[+\frac{GMm}{6R}\]
C) \[-\frac{GMm}{6R}\]
D) \[\frac{GMm}{2R}\]
Correct Answer: C
Solution :
Initial energy= \[-\frac{GMm}{R}+\frac{1}{2}\frac{GMm}{R}=-\frac{GMm}{2R}\] Final energy\[=-\frac{GMm/2}{2R/2}-\frac{-GMm/2}{2\times 3R/2}\] \[\Delta E=-\frac{GMm}{6R}\]You need to login to perform this action.
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