JEE Main & Advanced JEE Main Paper (Held On 15 April 2018) Slot-II

  • question_answer
    An unstable heavy nucleus at rest breaks into two nuclei which move away with velocities in the ratio of\[8:27\]. The ratio of the radii of the nuclei (assumed to be spherical ) is: [JEE Online 15-04-2018 (II)]

    A) \[8:27\]               

    B) \[2:3\]  

    C) \[3:2\]  

    D)          \[4:9\]

    Correct Answer: C

    Solution :

    \[\frac{{{V}_{1}}}{{{V}_{2}}}=\frac{8}{27}\] \[{{m}_{1}}{{V}_{1}}={{m}_{2}}{{V}_{2}}\] \[\frac{{{m}_{1}}}{{{m}_{2}}}=\frac{{{V}_{2}}}{{{V}_{1}}}=\frac{27}{8}\] \[\frac{\rho \times \frac{4}{3}\pi R_{1}^{3}}{\rho \times \frac{4}{3}\pi R_{2}^{3}}\] \[\left( \frac{{{R}_{1}}}{{{R}_{2}}} \right)={{\left( \frac{27}{8} \right)}^{\frac{1}{3}}}\] \[={{\left( \frac{3}{2} \right)}^{3\times \frac{1}{3}}}\] \[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{3}{2}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner