A) 100atm
B) 1 atm
C) 10 atm
D) 0.1 atm
Correct Answer: C
Solution :
\[\Delta G_{rxn}^{o}={{\Delta }_{f}}G{}^\circ (vapour)-{{\Delta }_{f}}G{}^\circ (liquid)\] \[\Delta G_{rxn}^{o}=103-100.7=2.3kcal/mol\] \[\Delta G_{rxn}^{o}=-RT\ln K\] \[\begin{align} & 2.3kcal/mol\times 1000cal/kcal= \\ & -2cal/mol/K\times 500K\times \ln K \\ \end{align}\] \[\ln K=2.3\] \[K=10atm=\]Vapour pressure of liquid 'S' Vapour pressure of liquid 'S' at 500 K is approximately equal to 10 atm.You need to login to perform this action.
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