JEE Main & Advanced JEE Main Paper (Held On 16 April 2018)

  • question_answer
    Let \[\vec{a}=\hat{i}+\hat{j}+\hat{k},\vec{c}=\hat{j}-\hat{k}\]and a vector \[\vec{b}\]be such that \[\vec{a}\times \vec{b}=\vec{c}\]and \[\vec{a}.\vec{b}=3.\]Then \[|\vec{b}|\]equals?

    A) \[\sqrt{\frac{11}{3}}\]                       

    B)  \[\sqrt{\frac{11}{3}}\]

    C)  \[\frac{11}{\sqrt{3}}\]                                  

    D)  \[\frac{11}{3}\]

    Correct Answer: A

    Solution :

     \[\vec{a}\times \vec{b}\times \vec{c}\]                 \[\Rightarrow \]\[|\vec{a}||\vec{b}|\sin \theta =|\vec{c}|\] \[\Rightarrow \]\[|\vec{a}||\vec{b}|\sin \theta =\sqrt{2}\]                                       ?[1] \[\vec{a}.\vec{b}=3\] \[\Rightarrow \]\[|\vec{a}||\vec{b}|\cos \theta =3\]                                    ?[2] Dividing [1] by [2], we get \[\tan \theta =\frac{\sqrt{2}}{3}\] \[\Rightarrow \]\[\sin \theta =\frac{\sqrt{2}}{\sqrt{11}}\] Substituting value of \[\sin \theta \]in [1], we get \[\Rightarrow \]\[|\vec{a}||\vec{b}||\sin \theta |=\sqrt{2}\] \[\Rightarrow \]\[\sqrt{3}|\vec{b}|\frac{\sqrt{2}}{\sqrt{11}}=\sqrt{2}\] \[|\vec{b}|=\frac{\sqrt{11}}{\sqrt{3}}\] Hence, answer is option A.


You need to login to perform this action.
You will be redirected in 3 sec spinner