A) 1100 Hz
B) 1000 Hz
C) 166 Hz
D) 100 Hz
Correct Answer: B
Solution :
Total length of sonometer wire, \[l=110cm=1.1m\] Length of wire is in ratio, 6 : 3 : 2 i.e. 60 cm, 30 cm, 20 cm. Tension in the wire, T = 400 N Mass per unit length, m = 0.01 kg Minimum common frequency = ? As we know, Frequency, \[v=\frac{1}{2}\sqrt{\frac{T}{m}}=\frac{1000}{11}Hz\] Similarly, \[{{v}_{1}}=\frac{1000}{6}Hz\] \[{{v}_{2}}=\frac{1000}{3}Hz\] \[{{v}_{3}}=\frac{1000}{2}Hz\] Hence common frequency = 1000 HzYou need to login to perform this action.
You will be redirected in
3 sec