A) 5 and 4.42
B) 4 and 4.00
C) 5 and 3.42
D) 3 and 5.42
Correct Answer: A
Solution :
Given \[{{\pi }_{ob}}=10.8atm\] \[{{\pi }_{nor}}=CST=0.10\times 0.0821\times 298=2.446\] now experimental value of (i) \[\text{=}\frac{\text{Observed osmotic pressure}}{\text{Normal osmotic pressure}}\]\[\text{=}\frac{10.8}{2.446}=4.42\]You need to login to perform this action.
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