JEE Main & Advanced
JEE Main Paper (Held On 19 April 2014)
question_answer
Nickel (Z = 28) combines with a uninegative monodentate ligand to form a diamagnetic complex \[{{[Ni{{L}_{4}}]}^{2-}}.\]The hybridisation involved and the number of unpaired electrons present in the complex are respectively:
JEE Main Online Paper (Held On 19 April 2016)
A)\[s{{p}^{3}},\] two
B)\[ds{{p}^{2}},\]zero
C)\[ds{{p}^{2}},\]one
D)\[s{{p}^{3}},\]zero
Correct Answer:
A
Solution :
\[{{[Ni{{L}_{4}}]}^{2-}}\] i.e, no. of unpaired electron = 2 hybridization \[-s{{p}^{3}}.\]