JEE Main & Advanced JEE Main Paper (Held On 19 April 2014)

  • question_answer
    A particle is released on a vertical smooth semicircular track from point X so that OX makes angle q from the vertical (see figure). The normal reaction of the track on the particle vanishes at point Y where OY makes angle \[\phi \] with the horizontal. Then:     JEE Main Online Paper (Held On 19 April 2016)

    A) \[\sin \phi =\cos \phi \]                

    B) \[\sin \phi =\frac{1}{2}\cos \theta \]

    C) \[\sin \phi =\frac{2}{3}\cos \theta \]      

    D) \[\sin \phi =\frac{3}{4}\cos \theta \]

    Correct Answer:


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