A) 8
B) 12
C) 10
D) 16
Correct Answer: B
Solution :
Required Area \[=\int\limits_{y=0}^{8}{{{y}^{1/3}}dy}\] \[\left. =\frac{{{y}^{{}^{1}/{}_{3}+1}}}{\frac{1}{3}+1} \right|_{0}^{8}\left. =\frac{3}{4}\left( {{y}^{{}^{4}/{}_{3}}} \right) \right|_{0}^{8}\] \[=\frac{3}{4}\left[ {{(8)}^{{}^{4}/{}_{3}}}-0 \right]=\frac{3}{4}\left[ {{2}^{4}} \right]\] \[=\frac{3}{4}\times 16=12\]sq. unit.You need to login to perform this action.
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