A) \[\theta ={{\tan }^{-1}}\left( \mu \right),F=\frac{\mu W}{\sqrt{1+{{\mu }^{2}}}}\]
B) \[\theta ={{\tan }^{-1}}\left( \frac{1}{\mu } \right),F=\frac{\mu W}{\sqrt{1+{{\mu }^{2}}}}\]
C) \[\theta =0,F=\mu W\]
D) \[\theta ={{\tan }^{-1}}\left( \frac{\mu }{1+\mu } \right),F=\frac{\mu W}{1+\mu }\]
Correct Answer: A
Solution :
Let the force F is applied at an angle \[\theta \] with the horizontal.You need to login to perform this action.
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